‘ü ‹ó”’ —{‚¤ ŒäŽål “ï‚¢ ‘Oi

hard_disk1.JPG What’s ƒU —‘z ‘ü ‹ó”’ —{‚¤ ‰—‚¢‚Ä ŒäŽål computer’s “ï‚¢ ‘Oi? Å‚à —LޝŽÒ has Š© ™Î ›–‚­‚à 20% ‘ü ‹ó”’ of ƒU “ï‚¢ ‘Oi ‚ׂ« be kept ‘ü ‚悤‚É –{ •Ê ‹ó”’ ‹X‚µ‚¢ be used ’™‚¦‚é —ÕŽž èk by —˜—p –› —p“r, defragmentation —\’èˆÄ, ƒIƒyƒŒ[ƒVƒ‡ƒ“ƒYƒŠƒT[ƒ` èk/ —\’èˆÄ ™Î –› ‰ÁŽZ •t‚« –› “dŽqŒvŽZ‹@. –› ‹X‚µ‚¢ ’†’† •t‚« ã‚èâ ŒäŽål “ï‚¢ ‘Oi ƒU ‘ü ‹ó”’ ŒäŽål “ï‚¢ ‘Oi has ŽE –¢–ž 20%.

‘債‚½: –{ is ƒAƒg ‹@ŠB ƒgƒ‰ƒ“ƒXƒŒ[ƒg ‹‹Žd which is provided " ˜Ô is" –³‚µ . ‹@ŠB–|–ó ‚©‚à‚µ‚ê‚È‚¢ “‚¢ •Ù‚¦‚é. —Ç‚¢ •t‘õ ‰p‘ –ñм whenever —L‚蓾‚ׂ«.

•Ê‚¯‘O –” •ª’S‹à ƒIƒyƒŒ[ƒVƒ‡ƒ“ƒYƒŠƒT[ƒ` ’¸‘Õ ‹Zp“I —Í –” —Í“Y‚¦ at ‰ä‚ª ƒfƒWƒ^ƒ‹ l¶ƒQ[ƒ ƒtƒH[ƒ‰ƒ.



“ó‚ ”½‰ž •ú‚Â‹ó”’ —{‚¤ ŒäŽål “ï‚¢ ‘Oi

  1. zden
    –í¶ 7th, 2007 1838:
    ˆë

    using —©‚è •t‚« gauge ƒU amt •K—p is not ‘¦•¨“I..

    20% of 100GB is 20Gb of ‘ü ‹ó”’ ‘΂µ‚Ä —ÕŽž èk is too —]’ö..

    –› Ž©Ì Šµ—á“I Šm• ›–‚­‚à 10GB ‘΂µ‚Ä —˜—p –” ƒIƒYƒŒƒCƒEƒBƒ“ƒOƒVƒXƒEƒ Žæ‘Ö ‹ó”’ •Ê‚Ä ƒU amt of •¨—“I –¼Žc is –¢–ž 1GB

    ‰ä‚ª $0.02 ’l‘Å‚¿ of ‰¼—ß..

  2. ƒ[ƒu ƒAƒg. van Donkelaar
    –í¶ 7th, 2007 2357:
    “ó‚Â

    ‹¤‚É ‘¸d •t‚« ŒäŽål ‘ü ‹ó”’ —\’è, ˆÈ‰º:

    –}‚» of dŽw, ƒIƒuƒU[ƒo[ ‚±‚ê‚ç –{‘¥:

    –³Ž‹ ƒtƒ‰ƒOƒƒ“ƒe[ƒVƒ‡ƒ“ Žñ”ö, ’¼ã 60% used ‰—‚¢‚Ä ƒAƒg harddrive ˆê —šs •s—lj» sets . ’¼ã [60sqrt2approx*(=. 1.484)]=% —šs is ŽÀ not ’l‘Å‚¿ ‹L, i.e. —] exponentially ’á—Ž! Defragmenting —Í •½ŠŠ not ˜J–ð.

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Š© ‘ü ‹ó”’ “ï‚¢ ‘Oi - ‘ü ‹ó”’ ‰—‚¢‚Ä “ï‚¢ ‘Oi - how do –› ’¸‘Õ ‹ó”’ ‰—‚¢‚Ä ‰ä‚ª ƒZƒ“ƒ` ‘Oi - ƒnƒEƒc[ ‘ü ‹ó”’ ƒZƒ“ƒ` ‘Oi - “ï‚¢ ‘Oi ‘ü ‹ó”’ - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ ‰—‚¢‚Ä “ï‚¢ ‘Oi - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ ‚ׂ« –› ’…—p ŒäŽål “ï‚¢ ‘Oi - ‘ü ‹ó”’ ƒZƒ“ƒ` ‘Oi - Š© ‘ü ‹ó”’ “ï‚¢ ‰¹”Õ - ‚Ç‚ñ‚È‚É ‘ü ‰¹”Õ ‹ó”’ ‚ׂ« –› have? - “ï‚¢ ‘Oi ‘ü ‹ó”’ —šs - ƒp[ƒZƒ“ƒg of —á Š© ‘΂µ‚Ä “ï‚¢ ‘Oi - ‘ü hardrive ‹ó”’ - what is —‘z ‘ü ‰¹”Õ ‹ó”’? - ‚Ç‚ñ‚È‚É “ï‚¢ ‘Oi ‹ó”’ ‚ׂ« –› ŠÕ ‘ü ‘΂µ‚Ä ‰“–] - ‚Ç‚ñ‚È‚É “ï‚¢ ‘Oi ‹ó”’ ‚ׂ« be ‘ü - ƒnƒEƒc[ ‘ü ‹ó”’ ‘Oi e - ‘ü ‹ó”’ ‰—‚¢‚Ä hardrive - ƒnƒEƒc[ ‘ü ‹ó”’ ‰—‚¢‚Ä harddrive - Š© ‘ü ‹ó”’ ‰—‚¢‚Ä ƒAƒg disc ‘Oi - —‘z “ï‚¢ ‘Oi ‘ü ‹ó”’ - ps3 ‰¹”Õ ‘ü ‹ó”’ - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ ‚ׂ« –› ’…—p ‰ä‚ª “ï‚¢ ‘Oi - ƒZƒ“ƒ` ‘Oi has —]’ö ® ‘ü ‹ó”’ - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ do –› •K—p ‰—‚¢‚Ä ŒäŽål “ï‚¢ ‘Oi - ‚Ç‚ñ‚È‚É ‘ü ‰¹”Õ ‹ó”’ ‚ׂ« ŠÕ - ƒnƒEƒc[ ŠM• ƒZƒ“ƒ` ‘OI ‘ü - —p“r —X•Ö ‹ó”’ ˜Ô “ï‚¢ ‘Oi - 20gb ‹ó”’ - Å‘å ‹ó”’ ‰—‚¢‚Ä hardrive - Š© ‘ü ‰¹”Õ ‹ó”’ ‰—‚¢‚Ä •ûŽ® ‘Oi - ‰“–] ”á•] Š© ‘ü ‹ó”’ - ‰“–] Š© ‘ü ‹ó”’ - ƒnƒEƒc[ ‘ü ‹ó”’ •ûŽ® ‘Oi - ƒnƒEƒc[ Šm• “ï‚¢ disc - how do –› ‘ü ‹ó”’ ‰—‚¢‚Ä ŒäŽål “ï‚¢ ‰¹”Õ ‘Oi - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ ‰—‚¢‚Ä ‘‹ ‘Oi - —‘z ‘ü ‰¹”Õ ‹ó”’ ‰“–] - ‘‹ ‚Ç‚ñ‚È‚É ‹ó”’ ‰—‚¢‚Ä “ï‚¢ ‘Oi - ‘‹ Š© ‘ü ‹ó”’ - ‘ü “ï‚¢ ‘Oi ‹ó”’ - ‚Ç‚ñ‚È‚É ‘ü ‹ó”’ is Š© ‰—‚¢‚Ä “ï‚¢ disc - how do –› E‚¢•¨ ŒäŽål ‘ü ‹ó”’ ‰—‚¢‚Ä ƒAƒg ‰¹”Õ - Šm• ŒäŽål own ‹ó”’ - –hŽ~ ‘‹ ‰“–] ‚æ‚è checking ƒU ‹ó”’ ‰—‚¢‚Ä ŒäŽål “ï‚¢ ‘Oi - Š© " ‘ü ‹ó”’" - Š© ‘ü ‹ó”’ ‰“–] •ûŽ® ‘Oi - "—‘z ‘ü ‹ó”’ of harddisk Ÿø‚Þ ‘‹ XP" - “ï‚¢ ‘Oi ‘ü ‹ó”’ —©‚è - ‚Ç‚ñ‚È‚É “ï‚¢ ‘Oi ‹ó”’ is Š© ‰—‚¢‚Ä ƒAƒg ƒT[ƒo[ ‘΂µ‚Ä virtualization? -